Ticket #1720 (closed bug: fixed)
fdiv_i_i_i and fdiv_i_i ops don't work correctly.
|Reported by:||tcurtis||Owned by:||NotFound|
fdiv is documented to be flooring division: "The result is the floor() of the division i.e. the next whole integer towards -inf."
The num variants of fdiv correctly perform flooring division.
The int variants of fdiv floor the result of C integer division of the arguments, and C integer division truncates towards zero. Therefore, fdiv_i_i_i is currently equivalent to div_i_i_i.